C++ program to check Palindrome number

In this chapter of C++ program tutorial out task is: 

• write a c++ program to check whether a number is palindrome or not using function

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C++ program to check Palindrome number

Below is the c++ program to check whether a number is palindrome or not using if statement and loop.

/*  Program Name : To check whether a number is Palindrome or not
    Program Author : Sayantan Bose
*/

#include <iostream>
#include <math.h>
using namespace std;

//This function returns number we get by reversing the inputed number.
int palindrome(int num)
{
    int r=0,sum=0,i,c;
    string n = to_string(num);
    c=n.size();
    c=(pow(10,c))/10;
 while(num!=0)
    {
        r=num%10;
        sum=sum+r*c;
        num=num/10;
        c=c/10;

    }
  return sum;
}

// This is the main function
int main() {

int num,sum=0;
    cout<<"Enter any number to check Palindrome:\n";
    cin>>num;
    int new_num;
    new_num=num;
 sum=palindrome(num);
  if(sum==new_num)
        cout<<num<<" is a Palindrome number";
    else
        cout<<num<< " is not a Palindrome number";

	return 0;
}

OUTPUT

• A number is said to be Palindrome if and only if the reverse of the number is equal to the number itself.
• For example: 121 is a Palindrome number. Because 121 when reversed gives 121  which is the number itself.   
• In the method palindrome, we are calculating the length of the number by converting it into a string. The number is reversed using the above logic and the reversed number is then returned to the main method.
• In the main method the reversed number is then compared with the original number provided as input.
• If both of them turn out to be equal the number is a Palindrome number else it isn't.