Print even series in shell script up to n terms

In this shell script program, we will learn to:

• print even series in shell script up to n terms. The number will be given by the user.

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Lets see algorithm, shell program and snapshot for how to print even series up to nth number in shell script.

 

ALGORITHM TO PRINT EVEN SERIES:

Given below is shell script to print even series from 1 to nth number:

STEP 1: START

STEP 2: DCLARE A VARIABLE (Suppose $checker) AND JUST INITIALIZE WITH 0.

STEP 3: READ NUMBER ( SUPPOSE num) FROM THE USER.

STEP 4:  RUN WHILE LOOP UPTO $num

STEP 5: GIVE WHILE LOOP CONDITION -> $checker –le $num

STEP 6: DIVIDE $checker BY 2 AND IF IT REMAINDER EQUAL TO ZERO THEN IT IS EVEN AND JUST PRINT IT

STEP 7: OTHERWISE INCREMENT $checker = $checker + 1

STEP 8: PRINT EVEN SERIES UPTO $num

STEP 9: STOP

 

CODE TO PRINT EVEN SERIES IN SHELL:

Given below is shell script to print even series from 1 to nth number:

#Print up to nth number of even series in shell script
clear
echo "------EVEN SERIES------"
echo -n "Enter a number: "
checker=0
read num
while test $checker -le $num
do
ii=`expr $checker % 2`
        if test $ii -eq 0
        then
                echo "$checker"
        fi
checker=`expr $checker + 1`
done

OUTPUT:

EXPLANATION:

• ‘if test $ii -eq 0’is used to check from 0 to nth numbers whether they are even or odd.
• If above condition is true then it is even and we should print it.
• Otherwise ‘$checker=$checker+1’ will be performed to check next digits.
• We have to remember that up to highest number (which will be given by the user) we have to perform loop operation.